Can Sin (1/0) have a finite value?

The expression [math]\sin(\dfrac{1}{0})[/math] is equivalent to [math]\sin(\dfrac{orange}{mango})[/math], i.e has no meaning.

On the other hand,

[math]\displaystyle \lim_\limits{x \to 0} \sin(\dfrac{1}{x}) [/math]does have a finite value, between [math]-1[/math] and [math]1[/math].

13 Replies to “Can Sin (1/0) have a finite value?”

  1. Sin(1/0) can be written as sin(1/x) where

    X is tending towards 0 or we can write it

    Lim x-0(1/x)

    It is clear from given function is defined for all values of x except 0 bcz at 0 it's value will be infinity .

    So the value of sin(1/0) doesn't exist.

  2. no,it can not be.

    because the range of sin function lies between -1 to +1.

    so for any value of domain, function (sinX) value can not be more then +1 or less then -1.

    hope it will make you understand.

    thank you.

  3. Yes, the value is finite. Explanation – as the value of sine function is always between -1 to +1, it'll not depend on the angel for being infinite. It's not possible to find the exact value but it must be difinite between -1 and +1.

  4. It is just a finite value between 1 and -1. But, one can't tell the exact value. Whatever you put in sine and cosine function……they just lie from -1 to 1.

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